Returns the element at a specified index in a sequence.
(in System.Core.dll)
Visual Basic (Declaration)
<ExtensionAttribute> _
Public Shared Function ElementAt(Of TSource) ( _
source As IEnumerable(Of TSource), _
index As Integer _
) As TSource
Dim source As IEnumerable(Of TSource)
Dim index As Integer
Dim returnValue As TSource
returnValue = source.ElementAt(index)
public static TSource ElementAt<TSource>(
this IEnumerable<TSource> source,
int index
)
[ExtensionAttribute]
public:
generic<typename TSource>
static TSource ElementAt(
IEnumerable<TSource>^ source,
int index
)
JScript does not support generic types or methods.
Type Parameters
- TSource
The type of the elements of source.
Return Value
Type: TSource
The element at the specified position in the source sequence.
Usage Note
In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<(Of <(TSource>)>). When you use instance method syntax to call this method, omit the first parameter. For more information, see Extension Methods (Visual Basic) or Extension Methods (C# Programming Guide).
If the type of source implements IList<(Of <(T>)>), that implementation is used to obtain the element at the specified index. Otherwise, this method obtains the specified element.
This method throws an exception if index is out of range. To instead return a default value when the specified index is out of range, use the ElementAtOrDefault<(Of <(TSource>)>) method.
The following code example demonstrates how to use ElementAt<(Of <(TSource>)>) to return an element at a specific position.
' Create an array of strings.
Dim names() As String = _
{"Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow", "Hedlund, Magnus", "Ito, Shu"}
Dim random As Random = New Random(DateTime.Now.Millisecond)
' Get a string at a random index within the array.
Dim name As String = names.ElementAt(random.Next(0, names.Length))
' Display the output.
MsgBox("The name chosen at random is " & name)
' This code produces the following output:
'
' The name chosen at random is Ito, Shu
string[] names =
{ "Hartono, Tommy", "Adams, Terry", "Andersen, Henriette Thaulow",
"Hedlund, Magnus", "Ito, Shu" };
Random random = new Random(DateTime.Now.Millisecond);
string name = names.ElementAt(random.Next(0, names.Length));
Console.WriteLine("The name chosen at random is '{0}'.", name);
/*
This code produces the following sample output:
The name chosen at random is 'Ito, Shu'.
*/
Windows 7, Windows Vista, Windows XP SP2, Windows Server 2008 R2, Windows Server 2008, Windows Server 2003, Windows CE, Windows Mobile for Smartphone, Windows Mobile for Pocket PC, Xbox 360, Zune
The .NET Framework and .NET Compact Framework do not support all versions of every platform. For a list of the supported versions, see .NET Framework System Requirements.
.NET Framework
Supported in: 3.5
.NET Compact Framework
Supported in: 3.5
XNA Framework
Supported in: 3.0
Reference