Use arithmetic operators to perform calculations in X++. Except for ~, which is unary, all arithmetic operators are dyadic; that is, they work on two operands. The syntax of arithmetic expressions is: expression1ArithmeticOperatorexpression2.
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Operator
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Term
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Description
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<<
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Left shift
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Performs expression2 left shift (a multiplication by 2) on expression1.
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>>
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Right shift
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Performs expression2 right shift (a division by 2) on expression1.
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*
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Multiply
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Multiplies expression1 by expression2.
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/
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Divide
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Divides expression1 by expression2.
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DIV
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Integer division
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Performs an integer division of expression1 by expression2.
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MOD
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Integer remainder
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Returns the remainder of an integer division of expression1 by expression2.
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~
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Not
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Unary operator. Performs a binary not-operation.
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&
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Binary AND
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Performs a binary and-operation on expression1 and expression2.
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^
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Binary XOR
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Performs a binary XOR-operation on expression1 and expression2.
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Binary OR
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Performs a binary or-operation on expression1 and expression2.
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+
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Plus
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Adds expression1 to expression2.
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-
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Minus
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Subtracts expression2 from expression1.
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?
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Ternary operator
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Takes three expressions: expression1 ? expression2 : expression3. If expression1 is true, expression2 is returned; otherwise, expression3 is returned.
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Operator
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Example
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Description
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<<
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i = 1 << 4;
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Performs 4 left shifts on 1 (1*2*2*2*2). This gives: i=16.
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>>
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i = 16 >> 4;
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Performs 4 right shifts on 16 (16/2/2/2/2). This gives i=1.
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*
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i = 4*5;
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Multiplies 4 by 5. i=20.
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/
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i = 20/5;
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Divides 20 by 5. i=4.
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div
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i = 100 div 21;
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Returns the integer division of 100 by 21. i=4 (4*21 = 84, remainder 16).
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mod
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i = 100 mod 21;
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Returns the remainder of the integer division of 100 by 21. i=16.
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~
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i = ~1;
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Binary negates 1. This gives i=-2 (all bits are reversed).
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&
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i = 1 & 3;
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Binary AND. Return the bits in common in the two integers. i=1.
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i = 1 | 3;
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Binary OR. Return the bits set in either 1 or 3. i=3.
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^
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i = 1 ^ 3;
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Binary XOR. Returns the bits set in 1 and NOT in 3 and vice versa. i=2.
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+
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i = 1 + 3;
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Adds 1 and 3. i=4.
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-
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i = 3 - 1;
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Subtracts 1 from 3. i=2.
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?
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i = (400>4) ? 1 : 5;
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If (400>4) 1 is returned, else 5 is returned. As 400>4, 1 is returned. i=1.
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