Int16.TryParse Method (String, Int16%)
Converts the string representation of a number to its 16-bit signed integer equivalent. A return value indicates whether the conversion succeeded or failed.
Namespace: System
Assembly: mscorlib (in mscorlib.dll)
Parameters
- s
- Type: System.String
A string containing a number to convert.
- result
- Type: System.Int16%
When this method returns, contains the 16-bit signed integer value equivalent to the number contained in s, if the conversion succeeded, or zero if the conversion failed. The conversion fails if the s parameter is null, is not of the correct format, or represents a number less than MinValue or greater than MaxValue. This parameter is passed uninitialized.
The Int16.TryParse(String, Int16) method differs from the Int16.Parse(String) method by returning a Boolean value that indicates whether the parse operation succeeded instead of returning the parsed Int16 value. It eliminates the need to use exception handling to test for a FormatException in the event that s is invalid and cannot be successfully parsed.
The s parameter should be the string representation of a number in the form:
[ws][sign]digits[ws]
Items in square brackets ([ and ]) are optional. The following table describes each element.
Element | Description |
|---|---|
ws | Optional white space. |
sign | An optional sign. |
digits | A sequence of digits ranging from 0 to 9. |
The s parameter is interpreted using the NumberStyles.Integer style. In addition to the byte value's decimal digits, only leading and trailing spaces together with a leading sign are allowed. To explicitly define the style elements together with the culture-specific formatting information that can be present in s, use the Int16.TryParse(String, NumberStyles, IFormatProvider, Int16) method.
The s parameter is parsed using the formatting information in a NumberFormatInfo object that is initialized for the current system culture. For more information, see CurrentInfo.
This overload of the TryParse method interprets all digits in the s parameter as decimal digits. To parse the string representation of a hexadecimal number, call the Int16.TryParse(String, NumberStyles, IFormatProvider, Int16) overload.
The following example calls the Int16.TryParse(String, Int16)method with a number of different string values.
using System; public class Example { public static void Demo(System.Windows.Controls.TextBlock outputBlock) { TryToParse(outputBlock, null); TryToParse(outputBlock, "16051"); TryToParse(outputBlock, "9432.0"); TryToParse(outputBlock, "16,667"); TryToParse(outputBlock, " -322 "); TryToParse(outputBlock, "+4302"); TryToParse(outputBlock, "(100);"); TryToParse(outputBlock, "01FA"); } private static void TryToParse(System.Windows.Controls.TextBlock outputBlock, string value) { short number; bool result = Int16.TryParse(value, out number); if (result) { outputBlock.Text += String.Format("Converted '{0}' to {1}.", value, number) + "\n"; } else { if (value == null) value = ""; outputBlock.Text += String.Format("Attempted conversion of '{0}' failed.", value) + "\n"; } } } // The example displays the following output: // Attempted conversion of '' failed. // Converted '16051' to 16051. // Attempted conversion of '9432.0' failed. // Attempted conversion of '16,667' failed. // Converted ' -322 ' to -322. // Converted '+4302' to 4302. // Attempted conversion of '(100)' failed. // Attempted conversion of '01FA' failed.
For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.