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Pointer Expressions (C++)

Any expression with an array type can be converted to a pointer of the same type. The result of the conversion is a pointer to the first array element. The following example demonstrates such a conversion:

char szPath[_MAX_PATH]; // Array of type char.
char *pszPath = szPath; // Equals &szPath[0].

An expression that results in a function returning a particular type is converted to a pointer to a function returning that type, except when:

  • The expression is used as an operand to the address-of operator (&).

  • The expression is used as an operand to the function-call operator.

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