Error Message
'identifier' : illegal use of this type as an expression
An expression uses the -> operator with a typedef identifier.
The following sample generates C2275:
// C2275.cpp
typedef struct S {
int mem;
} *S_t;
void func1( int *parm );
void func2() {
func1( &S_t->mem ); // C2275, S_t is a typedef
}