difftime
Visual Studio .NET 2003
Finds the difference between two times.
double difftime( time_t timer1, time_t timer0 );
Parameters
- timer1
- Ending time.
- timer0
- Beginning time.
Return Value
difftime returns the elapsed time in seconds, from timer0 to timer1. The value returned is a double-precision, floating-point number.
Remarks
The difftime function computes the difference between the two supplied time values timer0 and timer1.
Requirements
| Routine | Required header | Compatibility |
|---|---|---|
| difftime | <time.h> | ANSI, Win 98, Win Me, Win NT, Win 2000, Win XP |
For additional compatibility information, see Compatibility in the Introduction.
Libraries
All versions of the C run-time libraries.
Example
// crt_difftime.c
/* This program calculates the amount of time
* needed to do a floating-point multiply 500 million times.
*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main( void )
{
time_t start, finish;
long loop;
double result, elapsed_time;
printf( "Multiplying 2 floating point numbers 500 million times...\n" );
time( &start );
for( loop = 0; loop < 500000000; loop++ )
result = 3.63 * 5.27;
time( &finish );
elapsed_time = difftime( finish, start );
printf( "\nProgram takes %6.0f seconds.\n", elapsed_time );
}
Sample Output
Multiplying 2 floating point numbers 500 million times... Program takes 5 seconds.
See Also
Floating-Point Support Routines | Time Management Routines | time | Run-Time Routines and .NET Framework Equivalents
