floor, floorf
Visual Studio .NET 2003
Calculates the floor of a value.
double floor( double x ); float floor( float x ); // C++ only long double floor( long double x ); // C++ only float floorf( float x );
Parameter
- x
- Floating-point value.
Return Value
The floor function returns a floating-point value representing the largest integer that is less than or equal to x. There is no error return.
| Input | SEH Exception | Matherr Exception |
|---|---|---|
| ± QNAN,IND | none | _DOMAIN |
floor has an implementation that uses Streaming SIMD Extensions 2 (SSE2). See _set_SSE2_enable for information and restrictions on using the SSE2 implementation.
Remarks
C++ allows overloading, so you can call overloads of floor. In a C program, floor always takes and returns a double.
Requirements
| Function | Required header | Compatibility |
|---|---|---|
| floor, floorf | <math.h> | ANSI, Win 98, Win Me, Win NT, Win 2000, Win XP |
For additional compatibility information, see Compatibility in the Introduction.
Libraries
All versions of the C run-time libraries.
Example
// crt_floor.c
/* This example displays the largest integers
* less than or equal to the floating-point values 2.8
* and -2.8. It then shows the smallest integers greater
* than or equal to 2.8 and -2.8.
*/
#include <math.h>
#include <stdio.h>
int main( void )
{
double y;
y = floor( 2.8 );
printf( "The floor of 2.8 is %f\n", y );
y = floor( -2.8 );
printf( "The floor of -2.8 is %f\n", y );
y = ceil( 2.8 );
printf( "The ceil of 2.8 is %f\n", y );
y = ceil( -2.8 );
printf( "The ceil of -2.8 is %f\n", y );
}
Output
The floor of 2.8 is 2.000000 The floor of -2.8 is -3.000000 The ceil of 2.8 is 3.000000 The ceil of -2.8 is -2.000000
See Also
Floating-Point Support Routines | ceil | fmod | Run-Time Routines and .NET Framework Equivalents
