_memicmp, _memicmp_l
Compares characters in two buffers (case-insensitive).
int _memicmp( const void *buf1, const void *buf2, size_t count ); int _memicmp_l( const void *buf1, const void *buf2, size_t count, _locale_t locale );
The _memicmp function compares the first count characters of the two buffers buf1 and buf2 byte by byte. The comparison is not case-sensitive.
If either buf1 or buf2 is a null pointer, this function invokes an invalid parameter handler, as described in Parameter Validation. If execution is allowed to continue, the function returns _NLSCMPERROR and sets errno to EINVAL.
_memicmp uses the current locale for locale-dependent behavior; _memicmp_l is identical except that it uses the locale passed in instead. For more information, see Locale.
|
Routine |
Required header |
|---|---|
|
_memicmp |
<memory.h> or <string.h> |
|
_memicmp_l |
<memory.h> or <string.h> |
For more compatibility information, see Compatibility in the Introduction.
// crt_memicmp.c
// This program uses _memicmp to compare
// the first 29 letters of the strings named first and
// second without regard to the case of the letters.
#include <memory.h>
#include <stdio.h>
#include <string.h>
int main( void )
{
int result;
char first[] = "Those Who Will Not Learn from History";
char second[] = "THOSE WHO WILL NOT LEARN FROM their mistakes";
// Note that the 29th character is right here ^
printf( "Compare '%.29s' to '%.29s'\n", first, second );
result = _memicmp( first, second, 29 );
if( result < 0 )
printf( "First is less than second.\n" );
else if( result == 0 )
printf( "First is equal to second.\n" );
else if( result > 0 )
printf( "First is greater than second.\n" );
}
Compare 'Those Who Will Not Learn from' to 'THOSE WHO WILL NOT LEARN FROM' First is equal to second.
Not applicable. To call the standard C function, use PInvoke. For more information, see Platform Invoke Examples.
